document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=142972>Question 142972</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Michael has $2.25 in nickels, dimes, and quarters.  If he has 3 fewer dimes than quarters and as many nickels as the sum of the dimes and quarters, how many of each kind of coin does he have? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #104046 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=104046\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Michael has $2.25 in nickels, dimes, and quarters.  If he has 3 fewer dimes than quarters and as many nickels as the sum of the dimes and quarters, how many of each kind of coin does he have?<BR>\n" );
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document.write( "EQUATIONS:<BR>\n" );
document.write( "5n + 10d + 25q = 225<BR>\n" );
document.write( "0  + d   -  q  =   3<BR>\n" );
document.write( "n  - d   -  q  =   0<BR>\n" );
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document.write( "Solve by any means to get:<BR>\n" );
document.write( "n = 11 (# of nickels)<BR>\n" );
document.write( "d = 7  (# of dimes)<BR>\n" );
document.write( "q = 4  (# of quarters)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
document.write( "<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );