document.write( "Question 142990: Solve \"abs%28%282x-1%29%2F3%29%3E=5%2F6\" \n" ); document.write( "
Algebra.Com's Answer #104042 by jim_thompson5910(35256)\"\" \"About 
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\"abs%28%282x-1%29%2F3%29%3E=5%2F6\" Start with the given inequality\r
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\n" ); document.write( "\n" ); document.write( "Break up the absolute value (remember, if you have \"abs%28x%29%3E=a\", then \"x+%3C=+-a\" or \"x+%3E=+a\")\r
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\n" ); document.write( "\n" ); document.write( "\"%282x-1%29%2F3+%3C=+-5%2F6\" or \"%282x-1%29%2F3+%3E=5%2F6\" Break up the absolute value inequality using the given rule\r
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\n" ); document.write( "\n" ); document.write( "\"6%28%282x-1%29%2Fcross%283%29%29+%3C=+6%28-5%2Fcross%286%29%29\" or \"6%28%282x-1%29%2Fcross%283%29%29+%3E=+6%285%2Fcross%286%29%29\" Multiply both sides by the LCD 6 to clear the fractions\r
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\n" ); document.write( "\n" ); document.write( "\"2%282x-1%29+%3C=+-5\" or \"2%282x-1%29+%3E=+5\" Distribute and multiply\r
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\n" ); document.write( "\n" ); document.write( "\"4x-2+%3C=+-5\" or \"4x-2+%3E=+5\" Distribute again\r
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\n" ); document.write( "\n" ); document.write( "\"x%3C=+-3%2F4\" or \"x+%3E=+7%2F4\" Isolate x in each case\r
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\n" ); document.write( "\n" ); document.write( "So our solution is\r
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\n" ); document.write( "\n" ); document.write( "\"x%3C=+-3%2F4\" or \"x+%3E=+7%2F4\"\r
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\n" ); document.write( "\n" ); document.write( "which looks like this in interval notation\r
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