document.write( "Question 142978: For the following, solve. Find exact solutions\r
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\n" ); document.write( "\n" ); document.write( "\"x-2%2Asqrt%28x%29%2B1=0\"
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Algebra.Com's Answer #104028 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"x-2%2Asqrt%28x%29%2B1=0\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "Let \"y=sqrt%28x%29\". So this means that \"y%5E2=%28sqrt%28x%29%29%5E2=x\"\r
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\n" ); document.write( "\n" ); document.write( "\"y%5E2-2y%2B1=0\" Replace \"sqrt%28x%29\" with \"y\" replace \"x\" with \"y%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28y-1%29%28y-1%29=0\" Factor the left side (note: if you need help with factoring, check out this solver)\r
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\n" ); document.write( "\n" ); document.write( "Now set each factor equal to zero:\r
\n" ); document.write( "\n" ); document.write( "\"y-1=0\" or \"y-1=0\" \r
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\n" ); document.write( "\n" ); document.write( "\"y=1\" or \"y=1\" Now solve for y in each case\r
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\n" ); document.write( "\n" ); document.write( "Since we have a repeating answer, our only answer is \"y=1\"\r
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\n" ); document.write( "\n" ); document.write( "Remember, we let \"y=sqrt%28x%29\"\r
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\n" ); document.write( "\n" ); document.write( "So this means that \"sqrt%28x%29=1\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=1%5E2\" Square both sides\r
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\n" ); document.write( "\n" ); document.write( "\"x=1\" Simplify\r
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\n" ); document.write( "\n" ); document.write( "So our answer is \"x=1\"
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