document.write( "Question 142911: I have 2 triangles in a trapezoid. there is an \"X\" in the trapezoid coneecting corners and I need to find the height of 2 verticle triangles ( >< ) and one has the base of nine and the other a base of 15 (the bases of the triangles are the parallel lines in the trapezoid which has an area of 27) I need to find the height of a triangle with the base of 15! \n" ); document.write( "
Algebra.Com's Answer #104012 by psbhowmick(878)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Let the trapezoid be ABCD.
\n" ); document.write( "Given: AB = 15 units, CD = 9 units, Area of trapezoid ABCD = 27 sq units.
\n" ); document.write( "Draw CE, perpendicular to AB from C at E. Let CE = h units.
\n" ); document.write( "Observe that CE is the height for both the triangles ABC and ACD as their bases are parallel.\r
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\n" ); document.write( "\n" ); document.write( "Area of trapezoid ABCD
\n" ); document.write( "= Area of triangle ABC + Area of triangle ACD
\n" ); document.write( "= \"%281%2F2%29+x+15+x+h+%2B+%281%2F2%29+x+9+x+h\" sq units [since \"AREA+=+1%2F2\"\"x\"\"BASE\"\"x\"\"ALTITUDE\"]
\n" ); document.write( "= \"%281%2F2%29%2815h+%2B+9h%29\" sq units
\n" ); document.write( "= \"%281%2F2%2924h\" sq units
\n" ); document.write( "= \"12h\" sq units\r
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\n" ); document.write( "\n" ); document.write( "But area of trapezoid ABCD is given to be 27 sq units.
\n" ); document.write( "So, \"12h+=+27\"
\n" ); document.write( "\"h+=+9%2F4+=+2.25\" units\r
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\n" ); document.write( "\n" ); document.write( "Thus, required height is 2.25 units.
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