document.write( "Question 142918: I need help with this word problem which needs to be solved using a system of two linear equations. Thank you in advance for your help.\r
\n" ); document.write( "\n" ); document.write( "A university bookstore recently sold a wirebound graph-paper notebook for $2.50, and a college-ruled notebook for $2.30. At the start of spring semester, a combination of 50 of these notebooks were sold for a total of $118.60. How many of each type were sold?
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Algebra.Com's Answer #103992 by jojo14344(1513)\"\" \"About 
You can put this solution on YOUR website!
Sure!
\n" ); document.write( "First, Let's assigned \"x\" for wirebound notebk, and \"y' for college notebk, and we know the total is 50. Equating the fact, \"x+y=50\" right? -------- eqn 1
\n" ); document.write( "Next, $2.50 of each wirebound were sold PLUS $2.30 each of college also sold and total to $118.60. Equating that fact,
\n" ); document.write( "$2.50(x) + $2.30(y) = $118.60, isn't it? ----------- eqn 2
\n" ); document.write( "Go back eqn 1 we get \"y=50-x\" and substitute this value of y in eqn 2. Continuing,
\n" ); document.write( "$2.50(x) + $2.30(50-x) = $118.60
\n" ); document.write( "$2.50(x) + $115 -$2.30(x) = $118.60
\n" ); document.write( "$0.20(x) = $118.60-$115
\n" ); document.write( "$0.20(x) = $ $3.60
\n" ); document.write( "x= 18, total pieces for wirebound notebook
\n" ); document.write( "in eqn 1 we get y=50-18= 32 pieces, total for college ruled notebk
\n" ); document.write( "In doubt? Go back eqn 2,
\n" ); document.write( "$2.50(18) + $2.30(32) =$118.60
\n" ); document.write( "$45 + $73.60 = $118.60
\n" ); document.write( "$118.60 = $118.60, cool!
\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo
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