document.write( "Question 142851: At 9pm, Lucy started to gallop her horse at 20 miles per hour to catch Edmund, who had a three hour head start, and if Lucy was still 40 miles behind at 11 pm, how fast was Edmund riding?\r
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document.write( "(PS: Please show how you got your answer, so I can see how you worked it. This problem is giving me major problems. It has been explained to me 2 different ways, but I don't understand either way. Thanks.) \n" );
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Algebra.Com's Answer #103946 by psbhowmick(878)![]() ![]() You can put this solution on YOUR website! Suppose, Edmund's speed is 'v' mph. \n" ); document.write( "By that time Lucy rode for 2 hrs. (9 pm to 11 pm), Edmund rode for ( 2 + 3 =) 5 hrs. (since he started 3 hrs. early).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "By 11 pm Lucy had rode a distance \n" ); document.write( "By 11 pm Edmund had rode a distance \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since, still Lucy is 40 miles behind then, \n" ); document.write( "Distance covered by Lucy + 40 miles = Distance covered by Edmund \n" ); document.write( "40 + 40 = 5v \n" ); document.write( "5v = 80 \n" ); document.write( "v = 80/5 = 16\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hence, Edmund rode at the speed 16 mph. \n" ); document.write( " |