document.write( "Question 21508: Here is my problem:\r
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document.write( "A father and his two sons bought a drug store for $320,000. If the father
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document.write( "invested twice as much as the older son, and the older son invested
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document.write( "$45,000 less than twice the younger son, how much did the father and
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document.write( "his sons each invest?\r
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document.write( "This needs to be solved as a linear equation.
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document.write( "The answer is: younger son, $65,000; older son, $85,000; father $170,000\r
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document.write( "I started with:
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document.write( "Father = A, older son = B and younger son = C
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document.write( "A + B + C = 320,000
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document.write( "2B = A
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document.write( "2C - 45,000 = B\r
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document.write( "But I don't know where to go from there.
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document.write( "Any help would be appreciated, Thanks!
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document.write( "Sandy \n" );
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Algebra.Com's Answer #10392 by venugopalramana(3286)![]() ![]() You can put this solution on YOUR website! SEE MY COMMENTS BELOW \n" ); document.write( "---------------------------------------------------------------------- \n" ); document.write( "Here is my problem: \n" ); document.write( "A father and his two sons bought a drug store for $320,000. If the father \n" ); document.write( "invested twice as much as the older son, and the older son invested \n" ); document.write( "$45,000 less than twice the younger son, how much did the father and \n" ); document.write( "his sons each invest? \n" ); document.write( "This needs to be solved as a linear equation. \n" ); document.write( "The answer is: younger son, $65,000; older son, $85,000; father $170,000 \n" ); document.write( "I started with: \n" ); document.write( "Father = A, older son = B and younger son = C..........GOOD...BUT THERE IS A BETTER OPTION...THE LESS THE NUMBER OF UNKNOWNS THE BETTER..I SHALL SHOW IT SEPERATELY...FIRST LET US GO BY YOUR THINKING \n" ); document.write( "A + B + C = 320,000....VERY GOOD....BETTER NAME IT AS EQN.I \n" ); document.write( "2B = A........VERY GOOD ......BETTER NAME IT AS EQN.II \n" ); document.write( "2C - 45,000 = B .....EXCELLENT.....BETTER NAME IT AS EQN.III \n" ); document.write( "But I don't know where to go from there.....AS USUAL YOU ARE AT THE END OF THE TUNNEL ,BUT NOT ABLE TO SEE THE LIGHT...THINK IT OUT THIS WAY..WE HAVE 3 UNKNOWNS..A,B,C....SO WE NEED 3 INDEPENDENT RELATIONS TO FIND THEM...AND WE HAVE 3 EQNS.NUMBERED ABOVE...WE TRY TO MAKE 3 TO 2 AND FROM 2 TO 1 UNKNOWNS. \n" ); document.write( "EQN.I HAS ALL 3 UNKNOWNS..SO LET US KEEP IT OUT FOR SOME TIME...EQNS.II AND III HAVE ONLY 2 UNKNOWNS...SO LET US TAKE THEM...FROM EQN.II,WE HAVE A=2B............................EQN.IV \n" ); document.write( "SO LET US TRY TO FIND C ALSO INTERMS OF B FROM EQN.III. \n" ); document.write( "2C-45000=B \n" ); document.write( "2C=(B+45000) \n" ); document.write( "C=(B+45000)/2.................EQN.V \n" ); document.write( "NOW SUSTITUTE EQNS.IV AND V IN EQN.I \n" ); document.write( "2B+B+(B+45000)/2=320000 \n" ); document.write( "3B+(B+45000)/2=320000 \n" ); document.write( "MULTIPLY THROUGH OUT WITH 2 \n" ); document.write( " 6B+B+45000=640000 \n" ); document.write( "7B=640000-45000=595000 \n" ); document.write( "B=595000/7=85000 \n" ); document.write( "A=2B=170000 \n" ); document.write( "C=(B+45000)/2=65000 \n" ); document.write( "Any help would be appreciated, Thanks!..... \n" ); document.write( "Sandy \n" ); document.write( "NOW ON TO BETTER PRACTICE...TAKE ANY CONVENIENT UNKNOWN AS X ..HERE YOUNGER SON IS THE CONVENIENT CHOICE SO LET YOUNGER SON'S INVESTMENT=X \n" ); document.write( "TWICE THIS =2X \n" ); document.write( "LESS 45OOO IS =2X-45000=OLDER SON'S INVESTMENT \n" ); document.write( "TWICE THIS =2(2X-45000)=4X-90000=FATHER'S INVESTMENT \n" ); document.write( "BUT TOTAL INVESTMENT IS 3200000 \n" ); document.write( "SO X+2X-45000+4X-90000=320000 \n" ); document.write( "7X=320000+90000+45000=455000 \n" ); document.write( "X=65000...ETC..... \n" ); document.write( " \n" ); document.write( " |