document.write( "Question 142797: A bricklayer and an electrician together spend 90 hours working on a new house. If the bricklayer earns $12 per hour, the electrician earns $16 an hour, and the owner pays them a total of $1350 for their work, how many hours does each worker spend on the house? \n" ); document.write( "
Algebra.Com's Answer #103908 by ptaylor(2198) You can put this solution on YOUR website! Let x=amount of time spent by the bricklayer \n" ); document.write( "And let y=amount of time spent by the electrician\r \n" ); document.write( "\n" ); document.write( "Now we are told the following\r \n" ); document.write( "\n" ); document.write( "x+y=90----------------------------eq1 \n" ); document.write( "and \n" ); document.write( "12x+16y=1350 ($ understood)-----------------------eq2\r \n" ); document.write( "\n" ); document.write( "Multiply eq1 by 12: \n" ); document.write( "12x+12y=1080--------------------eq1a \n" ); document.write( "Subtract eq1a from eq2:\r \n" ); document.write( "\n" ); document.write( "4y=270 divide each side by 4 \n" ); document.write( "y=67.5 hours----------------------------amount of time spent by the electrician \n" ); document.write( "Substitute y=67.5 into eq1:\r \n" ); document.write( "\n" ); document.write( "x+67.5=90 add 67.5 to each side \n" ); document.write( "x+67.5-67.5=90-67.5 collect like terms\r \n" ); document.write( "\n" ); document.write( "x=22.5 hours-------------------------------time spent by the bricklayer\r \n" ); document.write( "\n" ); document.write( "CK\r \n" ); document.write( "\n" ); document.write( "67.5+22.5=90 \n" ); document.write( "90=90 \n" ); document.write( "and \n" ); document.write( "67.5*16+22.5*12=1350 \n" ); document.write( "1080+270=1350 \n" ); document.write( "1350=1350\r \n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor \n" ); document.write( " |