document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=2410>Question 2410</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Thanks for helping me sole the equations.  I sent an equation with error.<BR>\n" );
document.write( "this is the correct equations.\r<BR>\n" );
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document.write( "Solve for A and B in the following problem.\r<BR>\n" );
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document.write( "4A+B=16, 2A+3B=24\r<BR>\n" );
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document.write( "Thank you!<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #1039 by </B><A HREF=/tutors/aboutme.mpl?userid=gsmani_iyer><B>gsmani_iyer(201)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=gsmani_iyer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=gsmani_iyer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=1039\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  <BR>\n" );
document.write( "   4a + b = 16     ...    (1)<BR>\n" );
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document.write( "   2a + 3b = 24    ...    (2)<BR>\n" );
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document.write( "Eq.(1)*3, we get<BR>\n" );
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document.write( "   12a + 3b = 48    ...    (3)<BR>\n" );
document.write( "Eq.(3)-(2)<BR>\n" );
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document.write( "   10a = 24\r<BR>\n" );
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document.write( "   so, a = 2.4.   By substituting this value of a in eq.no.1, we get<BR>\n" );
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document.write( "   4*2.4 + b = 16<BR>\n" );
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document.write( "   b = 16 - (4*2.4) i.e  =   16 - 9.6<BR>\n" );
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document.write( "   b = 6.4\r<BR>\n" );
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document.write( "   a = 2.4;  b = 6.4;        Answer.<BR>\n" );
document.write( "   Is it clear now?\r<BR>\n" );
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document.write( "   gsm<BR>\n" );
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