document.write( "Question 21482: Could you please help me with this problem \r
\n" ); document.write( "\n" ); document.write( "Solve for x: \"4x%5E4%2B20x%5E2=-25\"
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Algebra.Com's Answer #10385 by venugopalramana(3286)\"\" \"About 
You can put this solution on YOUR website!
4x^4+20x^2=-25
\n" ); document.write( "4x^4+20x^2+25=0
\n" ); document.write( "(2x^2)^2+2*(2X^2)(5)+(5)^2=0............
\n" ); document.write( "USE THE FORMULA (A+B)^2=A^2+B^2+2AB..WE GET
\n" ); document.write( "(2X^2+5)^2=0
\n" ); document.write( "HENCE 2X^2+5=0
\n" ); document.write( "X=+SQ.RT.(-5/2)=+i*SQ.RT.(5/2)....OR....
\n" ); document.write( "X=-SQ.RT.(-5/2)=-i*SQ.RT.(5/2)....OR....
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