document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=21457>Question 21457</A>: <I><SPAN STYLE=\"word-break: break-all;\"> by weight, one alloy is 75%copper and 25%zinc. Another alloy is 42%copper and 58%zinc. How many grams of each or these are required to make 200 grams of an alloy that is 60% copper and 40% zinc? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #10384 by </B><A HREF=/tutors/aboutme.mpl?userid=Paul><B>Paul(988)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Paul><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=10384\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 0.75x+0.42(200-x)=0.6(200)<BR>\n" );
document.write( "0.75x+84-0.42x=120<BR>\n" );
document.write( "0.33x=36<BR>\n" );
document.write( "x=109<BR>\n" );
document.write( "200-109=91<BR>\n" );
document.write( "Hence for 75$ copper and 25% zine it's 109 grams and for other it's 91grams  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );