document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=142635>Question 142635</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/1592009425/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> The sum of two numbers is 64. If twice the smaller number is subtracted from the larger number, the result is 16. Find the two numbers.\r<BR>\n" );
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document.write( "THANKS FOR YOUR HELP:) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #103820 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=103820\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> X+Y=64 OR X=64-Y<BR>\n" );
document.write( "X-2Y=16<BR>\n" );
document.write( "NOW REPLACE X IN THIS EQUATION BY(64-Y) & SOLVE FOR Y.<BR>\n" );
document.write( "64-Y-2Y=16<BR>\n" );
document.write( "-3Y=16-64<BR>\n" );
document.write( "-3Y=-48<BR>\n" );
document.write( "Y=-48/-3<BR>\n" );
document.write( "Y=16 ANSWER FOR THE SMALLER NUMBER.<BR>\n" );
document.write( "X+16=64<BR>\n" );
document.write( "X=64-16<BR>\n" );
document.write( "X=48 ANSWER FOR THE LARGER NUMBER.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "48-2*16=16<BR>\n" );
document.write( "48-32=16<BR>\n" );
document.write( "16=16<BR>\n" );
document.write( " </SPAN>\n" );
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