document.write( "Question 142530This question is from textbook Intermediate Algebra
\n" ); document.write( ": PLEASE HELP !
\n" ); document.write( "George built a rectangular pen for his rabbit such that the length is 7ft. less than twice the width. If the perimeter is 40ft. what are the dimensions of the pen? \n" ); document.write( "
Algebra.Com's Answer #103804 by jojo14344(1513)\"\" \"About 
You can put this solution on YOUR website!
Well, simply we go to the formula for finding the perimeter(P) of a rectangle,
\n" ); document.write( "P=2(length + width)---------- eqn 1
\n" ); document.write( "We assigned \"x\" as the width measurement since it is unknown,and length= 2x-7ft,
\n" ); document.write( "being 7 less twice the width, make sense right?
\n" ); document.write( "Therefore substituting,
\n" ); document.write( "40= 2(2x-7 +x)
\n" ); document.write( "40=6x-14
\n" ); document.write( "x=(40+14)/6
\n" ); document.write( "x=9 ft, Width
\n" ); document.write( "And, L=2x-7=2(9)-7= 11ft, Length
\n" ); document.write( "In doubt? go back eqn 1,
\n" ); document.write( "P=2(L+W)
\n" ); document.write( "40=2(11+9)
\n" ); document.write( "40=2(20)
\n" ); document.write( "40=40 cool!
\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo
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