document.write( "Question 142584: Mike invested $6000 for one year. He invested part of it at 9% and the rest at 11%. At the end of the year he earned $624 in interest. How much did he invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #103788 by vleith(2983) ![]() You can put this solution on YOUR website! Total invested = 6000. \n" ); document.write( "Total earned = 624. \n" ); document.write( "Let x be the part invested at 0.09 \n" ); document.write( "Let y be the part invested at 0.11\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " |