document.write( "Question 142579: Here is my \"domain\" problem if it makes any sense:
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\n" ); document.write( " Find domain of the function y=2sqrt of 4x+10\r
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Algebra.Com's Answer #103781 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "\"2%2Asqrt%284x%2B10%29\" Start with the given expression\r
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\n" ); document.write( "\n" ); document.write( "Remember you cannot take the square root of a negative value. So that means the argument \"4x%2B10\" must be greater than or equal to zero \r
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\n" ); document.write( "\n" ); document.write( "\"4x%2B10%3E=0\" Set the inner expression greater than or equal to zero\r
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\n" ); document.write( "\n" ); document.write( "\"4x%3E=0-10\"Subtract 10 from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"4x%3E=-10\" Combine like terms on the right side\r
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\n" ); document.write( "\n" ); document.write( "\"x%3E=%28-10%29%2F%284%29\" Divide both sides by 4 to isolate x \r
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\n" ); document.write( "\n" ); document.write( "\"x%3E=-5+%2F+2\" Reduce\r
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\n" ); document.write( "\n" ); document.write( "So that means x must be greater than or equal to \"-5+%2F+2\" in order for x to be in the domain\r
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\n" ); document.write( "\n" ); document.write( "So the domain in set-builder notation is\r
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\n" ); document.write( "\n" ); document.write( "So here is the domain in interval notation: [\"-5+%2F+2\",)\r
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\n" ); document.write( "\n" ); document.write( "Notice if we graph \"y=2%2Asqrt%284x%2B10%29\" , we get\r
\n" ); document.write( "\n" ); document.write( "\"+graph%28+500%2C+500%2C+-10%2C+10%2C+-10%2C+10%2C+2%2Asqrt%284x%2B10%29%29+\" notice how the graph never crosses the line \"x=-5+%2F+2\". So this graphically verifies our answer.\r
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\n" ); document.write( "\n" ); document.write( "and we can see that x must be greater than or equal to \"-5+%2F+2\" in order to lie on the graph
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