document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=142581>Question 142581</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A twirler throws a baton with an initial upward velocity of 20 meters per second given by the equation: h(t)=20t-5tsquared.  When will the baton be back at the twirler's level? After how many seconds will the baton reach its maximum height? :) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #103780 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=103780\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 0=20t-5t^2 __ factoring __ 0=t(20-5t)\r<BR>\n" );
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document.write( "t=0 __ this is the starting position\r<BR>\n" );
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document.write( "20-5t=0 __ 20=5t __ 4=t __ this is the return to the start\r<BR>\n" );
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document.write( "time up=time down __ so max height is at 4/2 or 2 sec </SPAN>\n" );
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