document.write( "Question 142541: ok.\r
\n" ); document.write( "\n" ); document.write( "3y=9x+12\r
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\n" ); document.write( "\n" ); document.write( "i know you divide 3y by 3 to cancel it out so all you have is y.
\n" ); document.write( "and then i know you divide 12 by 3 to get 4.
\n" ); document.write( "this makes it y=9x+4.
\n" ); document.write( "do i also divide 9x by 3?
\n" ); document.write( "then the answer is
\n" ); document.write( "y=3x=4.
\n" ); document.write( "this looks more right.
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Algebra.Com's Answer #103758 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "\"3%2Ay=9%2Ax%2B12\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"y=%289%2Ax%2B12%29%2F%283%29\" Divide both sides by \"3\".\r
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\n" ); document.write( "\n" ); document.write( "\"y=%289%2Ax%29%2F%283%29%2B%2812%29%2F%283%29\" Break up the fraction\r
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\n" ); document.write( "\n" ); document.write( "\"y=3x%2B4\" Reduce \"9x%2F3\" to get \"3x\". Reduce \"12%2F3\" to get \"4\".\r
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\n" ); document.write( "\n" ); document.write( "So you are correct
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