document.write( "Question 142476: # If x2-x+1=0 is a factor of ax3+bx2+cx+d=0 then
\n" ); document.write( "a) d - a = b - 2c
\n" ); document.write( "b) a - d = b + 2c
\n" ); document.write( "c) a + d = b - 2c
\n" ); document.write( "explain clearly.........
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Algebra.Com's Answer #103719 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!
If \"x%5E2-x%2B1=0\" is a factor of \"ax%5E3%2Bbx%5E2%2Bcx%2Bd=0\" then
\n" ); document.write( "a) \"d+-+a+=+b+-+2c\"
\n" ); document.write( "b) \"a+-+d+=+b+%2B+2c\"
\n" ); document.write( "c) \"a+%2B+d+=+b+-+2c\"\r
\n" ); document.write( "\n" ); document.write( "\"x2-x%2B1=0\"………\"a=0\",\"+b=1\", \"c=-1\", \"d=1\"\r
\n" ); document.write( "\n" ); document.write( "Then:\r
\n" ); document.write( "\n" ); document.write( "a) \"1+-+0=+1+%962%28-1%29\"
\n" ); document.write( "\"1=1%2B2\"
\n" ); document.write( "\"1=3\"..........\"1\" is not equal to \"3\"\r
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\n" ); document.write( "\n" ); document.write( "b) \"0+-1+=+1+%2B+2%28-1%29\"
\n" ); document.write( " \"-1+=+1+%962\"
\n" ); document.write( "\"-1+=-1\"……………this is your answer\r
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\n" ); document.write( "\n" ); document.write( "c) \"0+%2B+1=+1+-2%28-1%29\"
\n" ); document.write( "\"1=1%2B2\"
\n" ); document.write( "\"1=3\".............\"1\" is not equal to \"3\"\r
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