document.write( "Question 142462: How are surface area and volume affected when the dimension of a box is quadrupled. \n" ); document.write( "
Algebra.Com's Answer #103699 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
Volume(V) of a box=Length(L) times Width(W) times Height(H) or:
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\n" ); document.write( "V=LWH --------------------------------------------eq1
\n" ); document.write( "now if we quadruple the dimensions, we have:\r
\n" ); document.write( "\n" ); document.write( "V1=4L*4W*4H=64LWH--------------------------------eq2
\n" ); document.write( "Substitute LWH=V from eq1 into eq2:\r
\n" ); document.write( "\n" ); document.write( "V1=64V
\n" ); document.write( "So, when we quadruple the dimensions, the volume is increased by a factor of 64\r
\n" ); document.write( "\n" ); document.write( "Surface Area(SA) of a box equals Area of Top plus Area of Bottom plus Area of Front plus Area of Back plus Area of Each Side
\n" ); document.write( "Area of Top plus Bottom=2LW
\n" ); document.write( "Area of Front plus Back=2WH
\n" ); document.write( "Area of the two Sides=2LH, so:\r
\n" ); document.write( "\n" ); document.write( "SA=2LW+2WH+2LH----------------------------------------eq3
\n" ); document.write( "now if we quadruple the dimensions, we have:\r
\n" ); document.write( "\n" ); document.write( "SA1=2*4L*4W+2*4W*4H+2*4L*4H and this equals
\n" ); document.write( "SA1=16(2LW)+16(2WH)+16(2LH) from the right side, factor out 16:\r
\n" ); document.write( "\n" ); document.write( "SA1=16(2LW+2WH+2LH)-----------------------------------------eq4
\n" ); document.write( "substitute 2LW+2WH+2LH=SA from eq3 into eq4 and we get:\r
\n" ); document.write( "\n" ); document.write( "SA1=16SA\r
\n" ); document.write( "\n" ); document.write( "So, when we quadruple the dimensions, the surface area is increased by a factor of 16\r
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\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor
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