document.write( "Question 142454: Use the given information to find \"sin+2%28phi%29\", \"cos+2%28phi%29\", \"tan+2%28phi%29\".\r
\n" ); document.write( "\n" ); document.write( "1. \"tan%28phi%29=1%2F2\", \"pi+%3C+phi+%3C=+%283pi%2F2%29\"\r
\n" ); document.write( "\n" ); document.write( "2. \"sec%28phi%29=-5%2F2\",\"pi%2F2+%3C+phi+%3C+pi\"\r
\n" ); document.write( "\n" ); document.write( "3. \"sin%28theta%29=3%2F5\", \"0+%3C+phi+%3C+pi%2F2\"\r
\n" ); document.write( "\n" ); document.write( "Any help is greatly appreciated.
\n" ); document.write( "Thanks,
\n" ); document.write( "Justin
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Algebra.Com's Answer #103697 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
Use the given information to find \"sin%282phi%29\", \"cos%282phi%29\", \"tan%282phi%29\".
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document.write( "Formulas needed are\r\n" );
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document.write( "\"sin%282phi%29=+2sin%28phi%29cos%28phi%29\" \r\n" );
document.write( "\"cos%282phi%29=2cos%5E2%28phi%29-1\"\r\n" );
document.write( "\"tan%282phi%29=sin%282phi%29%2Fcos%282phi%29+\"\r\n" );
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document.write( "1. \"tan%28phi%29=1%2F2\", \"pi+%3C+phi+%3C+%283pi%29%2F2%29\" \r\n" );
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document.write( "That's the THIRD quadrant.\r\n" );
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document.write( "Draw a picture of angle theta in the third quadrant\r\n" );
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document.write( "Since \"TANGENT+=+%28OPPOSITE%29%2F%28ADJACENT%29+=+y%2Fx\" \r\n" );
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document.write( "If theta were in the first quadrant, we'd let the \r\n" );
document.write( "numerator of \"1%2F2\" be y and the denominator of \r\n" );
document.write( "\"1%2F2\" be x.  But since theta is in the third \r\n" );
document.write( "quadrant, we have to make x and y both negative.  \r\n" );
document.write( "So take y, the opposite, as the negative of the \r\n" );
document.write( "numerator, -1, and take x to be the negative of \r\n" );
document.write( "the denominator, -2. \r\n" );
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document.write( "So plot the point (-2,-1) in the third quadrant and \r\n" );
document.write( "draw a radius to it and draw a perpendicular up to \r\n" );
document.write( "the x-axis, forming a right triangle:\r\n" );
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document.write( "Next we need to find r, the hypotenuse. We use the\r\n" );
document.write( "Pythagorean theorem:\r\n" );
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document.write( "\"r%5E2=x%5E2%2By%5E2\"\r\n" );
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document.write( "\"r%5E2=%28-2%29%5E2%2B%28-1%29%5E2\"\r\n" );
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document.write( "\"r%5E2=4%2B1\"\r\n" );
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document.write( "\"r%5E2=5\"\r\n" );
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document.write( "\"r=sqrt%285%29\"\r\n" );
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document.write( "So we label that:\r\n" );
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document.write( "Now we have \"x=-2\",\"y=-1\",\"r=sqrt%285%29\"\r\n" );
document.write( "And so \r\n" );
document.write( "\"sin%28phi%29=y%2Fr=%28-1%29%2F%28sqrt%285%29%29=-sqrt%285%29%2F5\"\r\n" );
document.write( "\"cos%28phi%29=y%2Fr=%28-2%29%2F%28sqrt%285%29%29=-2sqrt%285%29%2F5\"\r\n" );
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document.write( "Substituting in\r\n" );
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document.write( "\"sin%282phi%29=+2sin%28phi%29cos%28phi%29\" \r\n" );
document.write( "\"sin%282phi%29=+2%28-sqrt%285%29%2F5%29%28-2sqrt%285%29%2F5%29\"\r\n" );
document.write( "\"sin%282phi%29=+2%282%285%29%29%2F25+=+20%2F25=4%2F5++\"\r\n" );
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document.write( "Substituting in\r\n" );
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document.write( "\"cos%282phi%29=2cos%5E2%28phi%29-1\"\r\n" );
document.write( "\"cos%282phi%29=2%28%28-2sqrt%285%29%29%2F5%29%5E2-1\"\r\n" );
document.write( "\"cos%282phi%29=2%28+4%2A5+%29%2F25+%29-1\"\r\n" );
document.write( "\"cos%282phi%29=40%2F25-1\"\r\n" );
document.write( "\"cos%282phi%29=8%2F5-1\"\r\n" );
document.write( "\"cos%282phi%29=8%2F5-5%2F5\"\r\n" );
document.write( "\"cos%282phi%29=3%2F5\"\r\n" );
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document.write( "Substituting those values in:\r\n" );
document.write( "\"tan%282phi%29=sin%282phi%29%2Fcos%282phi%29+\"\r\n" );
document.write( "\"tan%282phi%29=%284%2F5%29%2F%283%2F5%29+\"\r\n" );
document.write( "\"tan%282phi%29=%284%2F5%29%285%2F3%29\"\r\n" );
document.write( "\"tan%282phi%29=%284%2Fcross%285%29%29%28cross%285%29%2F3%29\"\r\n" );
document.write( "\"tan%282phi%29=4%2F3\"\r\n" );
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document.write( "If I have time I'll come back and do the others.\r\n" );
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document.write( "Edwin
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