Algebra.Com's Answer #103697 by Edwin McCravy(20060)  You can put this solution on YOUR website! Use the given information to find , , . \n" );
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document.write( "Formulas needed are\r\n" );
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document.write( "1. , \r\n" );
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document.write( "That's the THIRD quadrant.\r\n" );
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document.write( "Draw a picture of angle theta in the third quadrant\r\n" );
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document.write( "Since \r\n" );
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document.write( "If theta were in the first quadrant, we'd let the \r\n" );
document.write( "numerator of be y and the denominator of \r\n" );
document.write( " be x. But since theta is in the third \r\n" );
document.write( "quadrant, we have to make x and y both negative. \r\n" );
document.write( "So take y, the opposite, as the negative of the \r\n" );
document.write( "numerator, -1, and take x to be the negative of \r\n" );
document.write( "the denominator, -2. \r\n" );
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document.write( "So plot the point (-2,-1) in the third quadrant and \r\n" );
document.write( "draw a radius to it and draw a perpendicular up to \r\n" );
document.write( "the x-axis, forming a right triangle:\r\n" );
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document.write( "Next we need to find r, the hypotenuse. We use the\r\n" );
document.write( "Pythagorean theorem:\r\n" );
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document.write( "So we label that:\r\n" );
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document.write( "Now we have , , \r\n" );
document.write( "And so \r\n" );
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document.write( "Substituting in\r\n" );
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document.write( "Substituting in\r\n" );
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document.write( "Substituting those values in:\r\n" );
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document.write( "If I have time I'll come back and do the others.\r\n" );
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document.write( "Edwin \r \n" );
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