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Algebra.Com's Answer #103683 by ilana(307) $\"\"$ $\"About$

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When you raise something to the third power, you multiply by itself 3 times. So (3a^3b^2)^3 = (3a^3b^2)*(3a^3b^2)*(3a^3b^2). But (3a^3b^2)^2 = (3a^3b^2)*(3a^3b^2). So that's two of the three from (3a^3b^2)*(3a^3b^2)*(3a^3b^2). So:
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