document.write( "Question 142421: i need help with factoring questions such as $\"+x%5E3+-+x%5E2+-+4x+%2B+4+=+0+\"$ \n" ); document.write( "

Algebra.Com's Answer #103647 by luckycarebear4(1) $\"\"$ $\"About$

You can put this solution on YOUR website!
factor by grouping: $\"+x%5E3+-+x%5E2+\"$ is $\"+%28x%5E2%29%28x-1%29+\"$ and
\n" ); document.write( " $\"+-4x+%2B+4+\"$ is $\"+%28-4%29%28x+-+1%29+\"$ } then combine like terms in a way: $\"+%28x%5E2%29%28x-1%29+\"$ and $\"+%28-4%29%28x+-+1%29\"$ } have $\"+%28x-1%29+\"$ in common take that and mult by whats left: $\"+%28x-1%29%28x%5E2-4%29+\"$ . to finish solving set (each quantity in brackets) equal to zero: $\"+x-1+=+0+\"$ so add one to both sides and you get $\"+x=+1+\"$ and $\"+%28x%5E2%29-4+=0+\"$ so add 4 to both sides and you get $\"+%28x%5E2%29=4+\"$ , take the square root of both sides which cancels the 2nd power and you get $\"+x=+square+root+of+4\"$ which is $\"+x=2+\"$ so your solution is x= 1 and x=2. \n" ); document.write( "

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