document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=142395>Question 142395</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Car rental agency A will rent a car for $35 per day and an additional charge of $.24 per mile.  Car rental agency B will only charge $.16 per mile but charges $41 per day.  If adam wanted to rent a car for 3 days, how many miles would adam have to drive to make car rental agency b a better bargain? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #103641 by </B><A HREF=/tutors/aboutme.mpl?userid=jojo14344><B>jojo14344(1513)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jojo14344><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=103641\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First, we'll make an equation for both car rental on how much they will charge. And we'll refer on these equations in making car rental B a better bargain.<BR>\n" );
document.write( "For A = Rate ($/day) + 0.24* # of miles ------ eqn 1<BR>\n" );
document.write( "For B = Rate ($/day) + 0.16* # of miles ------ eqn 2<BR>\n" );
document.write( "We know the Rate but we don't know the # of miles he needs to travel, if we do trial and errror could take a awhile right?<BR>\n" );
document.write( "So if we can exlude first the \"rate of # of miles\" in both eqn. and we'll see;<BR>\n" );
document.write( "For A = $35/day * 3days= $105<BR>\n" );
document.write( "For B = $41/day * 3days= $123<BR>\n" );
document.write( "So you see in 3 days, B is +$18. Therefore, Adam needs to drive more in 3days to get the better deal right? How much more? And that's we'll find out,<BR>\n" );
document.write( "We use the \"rate of # of miles for both then\", and plus $19 on A to get over the plus $18 of B, so B will be cheaper. To show,<BR>\n" );
document.write( "Since # of miles unknown, we'll assign \"x\" to it,<BR>\n" );
document.write( "Rate of A + $19 = Rate of B<BR>\n" );
document.write( "$0.24* x(# of miles) +$19 = $0.16* x(# of miles)<BR>\n" );
document.write( "$0.24x-$0.16x=-$19<BR>\n" );
document.write( "$0.08x=-$19<BR>\n" );
document.write( "x=-237.50 miles. There's no negative(-) miles, so we use 237.50 miles!<BR>\n" );
document.write( "This is the total # of miles (minimum) Adam needs to travel so he can start his savings. To show that<BR>\n" );
document.write( "For A, as per eqn 1 =($35*3days) + ($0.24*237.50mi)= $105+$57<BR>\n" );
document.write( "A=$162<BR>\n" );
document.write( "For B, as per eqn 2 =($41*3days) + ($0.41*237.50mi)=$123+$38<BR>\n" );
document.write( "B=$161<BR>\n" );
document.write( "There you go! Adam can start getting a dollar($1) cheaper if he drives at least 237.50miles in 3 days. The more miles he drives, the more savings he can get (if he compare it to Car Rental A)<BR>\n" );
document.write( "Thank you,<BR>\n" );
document.write( "Jojo\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );