document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=142369>Question 142369</A>: <I><SPAN STYLE=\"word-break: break-all;\"> still having problems helping my son, please help. the problem is 3/2d2 + 4/3d<BR>\n" );
document.write( "the examples in the book are not very clear to myself or my son\r<BR>\n" );
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document.write( "Thankyou theodore uzonyi </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #103638 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=103638\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%283%2F2d%5E2%29%2B4%2F3d ALIGN=MIDDLE  ALT=\"%283%2F2d%5E2%29%2B4%2F3d\"   DISABLED_style= \"max-width:90%; height:auto;\" >  We want to get a \"Lowest Common Denominator (LCD)\" for these two fractions.  The LCD is the smallest number that both 2d^2 and 3d will divide evenly into.  By inspection, we can see that the LCD is 6d^2.  We'll now multiply each term by 6d^2/6d^2 (which equals 1) and when we do that we will have reduced the expression to one fraction instead of two.  When we do this we get:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%289%2B8d%29%2F6d%5E2 ALIGN=MIDDLE  ALT=\"%289%2B8d%29%2F6d%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > \r<BR>\n" );
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document.write( "Hope this helps---ptaylor </SPAN>\n" );
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