document.write( "Question 142361This question is from textbook
\n" ); document.write( ": Find the slope of the line that passes throught the points (-3,-6)and (1,6). \n" ); document.write( "
Algebra.Com's Answer #103629 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Let's denote the first point (-3,-6) as . In other words, and \r
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\n" ); document.write( "\n" ); document.write( "Now let's denote the second point (1,6) as . In other words, and \r
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\n" ); document.write( "\n" ); document.write( "\"m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29\" Start with the slope formula\r
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\n" ); document.write( "\n" ); document.write( "\"m=%286--6%29%2F%281--3%29\" Plug in \"y%5B2%5D=6\",\"y%5B1%5D=-6\",\"x%5B2%5D=1\",\"x%5B1%5D=-3\"\r
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\n" ); document.write( "\n" ); document.write( "\"m=12%2F4\" Subtract the terms in the numerator \"6--6\" to get \"12\". Subtract the terms in the denominator \"1--3\" to get \"4\"\r
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\n" ); document.write( "\n" ); document.write( "\"m=3\" Reduce\r
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\n" ); document.write( "\n" ); document.write( "So the slope of the line through the points (-3,-6) and (1,6) is \"m=3\"
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