document.write( "Question 142299: I really need some help. the square root of 3x^4y^3 divided the sqaure root of 9xy^5 The only thing I thought to do was to put the problems vertical instead of horizontal and then get the square root of 9. Im not sure what the next step is. \n" ); document.write( "
Algebra.Com's Answer #103603 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
square root of 3x^4y^3 divided the sqaure root of 9xy^5
\n" ); document.write( "-----------\r
\n" ); document.write( "\n" ); document.write( "= sqrt[3x^4y^3/9xy^5]\r
\n" ); document.write( "\n" ); document.write( "Multiply numerator and denominator by xy so the denominator becomes
\n" ); document.write( "a perfect square:\r
\n" ); document.write( "\n" ); document.write( "= sqrt[3x^5y^4/9x^2y^6]\r
\n" ); document.write( "\n" ); document.write( "Simplify the denominator:\r
\n" ); document.write( "\n" ); document.write( "= sqrt[3x^5y^4] / 3xy^3\r
\n" ); document.write( "\n" ); document.write( "Simplify the numerator:\r
\n" ); document.write( "\n" ); document.write( "= [x^2y^2/3xy^3] sqrt(3x)\r
\n" ); document.write( "\n" ); document.write( "Reduce the fraction:\r
\n" ); document.write( "\n" ); document.write( "= [x/3y]*sqrt(3x)
\n" ); document.write( "===================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
\n" );