document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=142304>Question 142304</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Im having trouble with this one. The sqaure root of 12x^2y^3 - the sqaure root of 27x^4y. When I tried to solve it I got 2xy^2the square root of y minus 3x^2the sqaure root of y. It just doesnt seem right to me. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #103596 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=103596\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The sqaure root of 12x^2y^3 - the sqaure root of 27x^4y.<BR>\n" );
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document.write( "sqrt(12x^2y^3) - sqrt(27x^4y)\r<BR>\n" );
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document.write( "= sqrt(4x^2y^2 * 3y) - sqrt(9x^4 * 3y)\r<BR>\n" );
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document.write( "= 2xy sqrt(3y) - 4x^2 sqrt(3y)\r<BR>\n" );
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document.write( "Factor to get:<BR>\n" );
document.write( "= (2xy - 4x^2)sqrt(3y)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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