document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=21318>Question 21318</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the randolphs use 12 more gallons of oil in oct than in sept. and twice as much in nov as in sept. if they used 132 gallons for 3 months, how much was used during each month? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #10355 by </B><A HREF=/tutors/aboutme.mpl?userid=bonster><B>bonster(299)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=bonster><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=10355\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> oct=12 more than sept\r<BR>\n" );
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document.write( "sept=x<BR>\n" );
document.write( "oct=x+12<BR>\n" );
document.write( "nov=twice as much as sept <BR>\n" );
document.write( "nov=2x\r<BR>\n" );
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document.write( "to find how much they used each month, add them up and equate it to 132<BR>\n" );
document.write( "x+x+12+2x=132<BR>\n" );
document.write( "4x+12=132<BR>\n" );
document.write( "4x=120<BR>\n" );
document.write( "x=30\r<BR>\n" );
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document.write( "sept=x=30<BR>\n" );
document.write( "oct=x+12= 30+12=42<BR>\n" );
document.write( "nov=2x=2(30)=60\r<BR>\n" );
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document.write( "check:<BR>\n" );
document.write( "30+42+60=132 </SPAN>\n" );
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