document.write( "Question 142171: Factor the following 3z^2-10z-25 \n" ); document.write( "
Algebra.Com's Answer #103519 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Looking at \"3z%5E2-10z-25\" we can see that the first term is \"3z%5E2\" and the last term is \"-25\" where the coefficients are 3 and -25 respectively.\r
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\n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient 3 and the last coefficient -25 to get -75. Now what two numbers multiply to -75 and add to the middle coefficient -10? Let's list all of the factors of -75:\r
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\n" ); document.write( "\n" ); document.write( "Factors of -75:\r
\n" ); document.write( "\n" ); document.write( "1,3,5,15,25,75\r
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\n" ); document.write( "\n" ); document.write( "-1,-3,-5,-15,-25,-75 ...List the negative factors as well. This will allow us to find all possible combinations\r
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\n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to -75\r
\n" ); document.write( "\n" ); document.write( "(1)*(-75)\r
\n" ); document.write( "\n" ); document.write( "(3)*(-25)\r
\n" ); document.write( "\n" ); document.write( "(5)*(-15)\r
\n" ); document.write( "\n" ); document.write( "(-1)*(75)\r
\n" ); document.write( "\n" ); document.write( "(-3)*(25)\r
\n" ); document.write( "\n" ); document.write( "(-5)*(15)\r
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\n" ); document.write( "\n" ); document.write( "note: remember, the product of a negative and a positive number is a negative number\r
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\n" ); document.write( "\n" ); document.write( "Now which of these pairs add to -10? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to -10\r
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First NumberSecond NumberSum
1-751+(-75)=-74
3-253+(-25)=-22
5-155+(-15)=-10
-175-1+75=74
-325-3+25=22
-515-5+15=10
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\n" ); document.write( "\n" ); document.write( "From this list we can see that 5 and -15 add up to -10 and multiply to -75\r
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\n" ); document.write( "\n" ); document.write( "Now looking at the expression \"3z%5E2-10z-25\", replace \"-10z\" with \"5z%2B-15z\" (notice \"5z%2B-15z\" adds up to \"-10z\". So it is equivalent to \"-10z\")\r
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\n" ); document.write( "\n" ); document.write( "\"3z%5E2%2Bhighlight%285z%2B-15z%29%2B-25\"\r
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\n" ); document.write( "\n" ); document.write( "Now let's factor \"3z%5E2%2B5z-15z-25\" by grouping:\r
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\n" ); document.write( "\n" ); document.write( "\"%283z%5E2%2B5z%29%2B%28-15z-25%29\" Group like terms\r
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\n" ); document.write( "\n" ); document.write( "\"z%283z%2B5%29-5%283z%2B5%29\" Factor out the GCF of \"z\" out of the first group. Factor out the GCF of \"-5\" out of the second group\r
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\n" ); document.write( "\n" ); document.write( "\"%28z-5%29%283z%2B5%29\" Since we have a common term of \"3z%2B5\", we can combine like terms\r
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\n" ); document.write( "\n" ); document.write( "So \"3z%5E2%2B5z-15z-25\" factors to \"%28z-5%29%283z%2B5%29\"\r
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\n" ); document.write( "\n" ); document.write( "So this also means that \"3z%5E2-10z-25\" factors to \"%28z-5%29%283z%2B5%29\" (since \"3z%5E2-10z-25\" is equivalent to \"3z%5E2%2B5z-15z-25\")\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So \"3z%5E2-10z-25\" factors to \"%28z-5%29%283z%2B5%29\" \r
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