document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=142127>Question 142127</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the dimensions of a rectangle whose area is 60cm squared and whose perimeter is 38cm. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #103499 by </B><A HREF=/tutors/aboutme.mpl?userid=nabla><B>nabla(475)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nabla><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=103499\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a=l*w<BR>\n" );
document.write( "p=2l+2w\r<BR>\n" );
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document.write( "60=l*w  implies w=60/l<BR>\n" );
document.write( "38=2l+2w\r<BR>\n" );
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document.write( "substitute w the equation for w into the second equation:\r<BR>\n" );
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document.write( "38=2l+2*60/l<BR>\n" );
document.write( "38=2l+120/l<BR>\n" );
document.write( "19=l+60/l<BR>\n" );
document.write( "19l=l^2+60<BR>\n" );
document.write( "0=l^2-19l+60<BR>\n" );
document.write( "0=(l-15)(l-4)\r<BR>\n" );
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document.write( "gives l=15 or l=4<BR>\n" );
document.write( "From the first equation, 16=4w implies 4=w.<BR>\n" );
document.write( "The dimensions are 15x4.<BR>\n" );
document.write( "Check:<BR>\n" );
document.write( "15*4=60\r<BR>\n" );
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document.write( "15*2+4*2=30+8=38<BR>\n" );
document.write( " </SPAN>\n" );
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