document.write( "Question 142143: Find the sum of the first 12 terms of the arithmetic series.
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document.write( "-5 + 0 + 5 +10 + ... \n" );
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Algebra.Com's Answer #103494 by nabla(475)![]() ![]() ![]() You can put this solution on YOUR website! The sum of the first n terms of an arithmetic progression is \n" ); document.write( "\n" ); document.write( "n=12 <--- # of terms \n" ); document.write( "a=-5 <--starting term \n" ); document.write( "r=5 <--- common difference between terms\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "s= \n" ); document.write( "= \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We can check by iterating every term:\r \n" ); document.write( "\n" ); document.write( "-5+0+5+10+15+20+25+30+35+40+45+50=270. \n" ); document.write( " |