document.write( "Question 142143: Find the sum of the first 12 terms of the arithmetic series.
\n" ); document.write( "-5 + 0 + 5 +10 + ...
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Algebra.Com's Answer #103494 by nabla(475)\"\" \"About 
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The sum of the first n terms of an arithmetic progression is \"na%2B%28n%28n-1%29r%29%2F2\".\r
\n" ); document.write( "\n" ); document.write( "n=12 <--- # of terms
\n" ); document.write( "a=-5 <--starting term
\n" ); document.write( "r=5 <--- common difference between terms\r
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\n" ); document.write( "\n" ); document.write( "s=\"12%2A%28-5%29%2B%2812%2812-1%295%29%2F2\"
\n" ); document.write( "=\"-60%2B330=270\"\r
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\n" ); document.write( "\n" ); document.write( "We can check by iterating every term:\r
\n" ); document.write( "\n" ); document.write( "-5+0+5+10+15+20+25+30+35+40+45+50=270.
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