document.write( "Question 142126: the product of two positive numbers is 1, and the sum of their squares is 82/9. Find these numbers. (My last post didn't supply enough info, sorry.) \n" ); document.write( "
Algebra.Com's Answer #103493 by edjones(8007) You can put this solution on YOUR website! Let b be one and s be the other. \n" ); document.write( "bs=1 \n" ); document.write( "b^2+s^2=82/9 \n" ); document.write( ". \n" ); document.write( "b=1/s \n" ); document.write( "(1/s)^2+s^2=82/9 \n" ); document.write( "1/s^2 + s^2=82/9 \n" ); document.write( "9+9s^4=82s^2 \n" ); document.write( "9s^4-82s^2+9=0 \n" ); document.write( "9s^4-81s^2-s^2+9=0 Factoring by grouping. \n" ); document.write( "9s^2(s^2-9)-(s^2-9)=0 \n" ); document.write( "(9s^2-1)(s^2-9)=0 \n" ); document.write( "(3s+1)(3s-1)(s+3)(s-3)=0 \n" ); document.write( "3s=1 s=1/3 \n" ); document.write( "s=3 \n" ); document.write( ". \n" ); document.write( "Check: \n" ); document.write( "3* 1/3 = 1 true \n" ); document.write( "3^2+(1/3)^2=9 1/9 =82/9 true \n" ); document.write( ". \n" ); document.write( "Ed \n" ); document.write( " \n" ); document.write( " |