document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=142129>Question 142129</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the area of a rectangle if three of its corners are (-0.1,-3.4), (-7.9,-3.4), and (-0.1,6.8). </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #103490 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=103490\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The 4th corner is (-7.9,6.8)<BR>\n" );
document.write( "subtract the x's from each other and the y's from each other to find the lengths of the sides.<BR>\n" );
document.write( "-7.9-(-0.1)=-7.9+0.1=7.8 The length is always positive.<BR>\n" );
document.write( "6.8-(-3.4)=6.8+3.4=10.2<BR>\n" );
document.write( "10.2*7.8=79.56<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
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