document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=142045>Question 142045</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A circle has a chord of length 8 that is tangent to a smaller, concentric circle.  Find the area between the two circles?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #103484 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=103484\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a line drawn from the center of the circles to the center of the chord is perpendicular to the chord\r<BR>\n" );
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document.write( "the radius of the larger circle (R), the radius of the smaller circle (r), and half of the chord (4)<BR>\n" );
document.write( "__ from a right triangle with the larger radius as the hypotenuse\r<BR>\n" );
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document.write( "by Pythagoras, r^2+4^2=R^2 __ subtracting r^2 __ 16=R^2-r^2\r<BR>\n" );
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document.write( "multiplying by pi __ 16(pi)=(pi)R^2-(pi)r^2 __ this is the area between the circles </SPAN>\n" );
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