document.write( "Question 142019: A total of $8000 is invested , part at 3% and the rest at 4% per year. If the annual return on theses investments is $275, how much is invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #103449 by checkley77(12844)\"\" \"About 
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.04x+.03(8000-x)=275
\n" ); document.write( ".04x+240-.03x=275
\n" ); document.write( ".01x=275-240
\n" ); document.write( ".01x=35
\n" ); document.write( "x=35/.01
\n" ); document.write( "x=3500 invested @ 4%
\n" ); document.write( "8000-3500=4500 invested @ 3%
\n" ); document.write( "proof:
\n" ); document.write( ".04*3500+.03*4500=275
\n" ); document.write( "140+135=275
\n" ); document.write( "275=275
\n" ); document.write( "
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