document.write( "Question 142053: The point (-1/2,sqrt3/2) on the unit circle is rotated 60 degrees clockwise. Determine the coordinates of the new point. \n" ); document.write( "
Algebra.Com's Answer #103439 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The point (-1/2,sqrt3/2) on the unit circle is rotated 60 degrees clockwise. Determine the coordinates of the new point. \n" ); document.write( "------------ \n" ); document.write( "The point is in the 2nd Quadrant. \n" ); document.write( "The reference angle is inverse sin(1/2) and inverse cos(sqrt(3)/2) is \n" ); document.write( "30 degrees. \n" ); document.write( "--------------------- \n" ); document.write( "The angle of the given point in the 2nd quadrant is 180-30 = 150 degrees \n" ); document.write( "--------- \n" ); document.write( "You rotate 60 degrees clockwise and end up at 90 degrees \n" ); document.write( "where the coordinates are (0,1). \n" ); document.write( "--------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |