document.write( "Question 142053: The point (-1/2,sqrt3/2) on the unit circle is rotated 60 degrees clockwise. Determine the coordinates of the new point. \n" ); document.write( "
Algebra.Com's Answer #103439 by stanbon(75887)\"\" \"About 
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The point (-1/2,sqrt3/2) on the unit circle is rotated 60 degrees clockwise. Determine the coordinates of the new point.
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\n" ); document.write( "The point is in the 2nd Quadrant.
\n" ); document.write( "The reference angle is inverse sin(1/2) and inverse cos(sqrt(3)/2) is
\n" ); document.write( "30 degrees.
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\n" ); document.write( "The angle of the given point in the 2nd quadrant is 180-30 = 150 degrees
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\n" ); document.write( "You rotate 60 degrees clockwise and end up at 90 degrees
\n" ); document.write( "where the coordinates are (0,1).
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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