document.write( "Question 142050: What is the complete solution to the equation /3-6x/=15? \n" ); document.write( "
Algebra.Com's Answer #103432 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\"abs%283-6x%29=15\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "Break up the absolute value (remember, if you have \"abs%28x%29=a\", then \"x=-a\" or \"x=a\")\r
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\n" ); document.write( "\n" ); document.write( "\"3-6x=-15\" or \"3-6x=15\" Set the expression \"3-6x\" equal to the original value 15 and it's opposite -15\r
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\n" ); document.write( "\n" ); document.write( "Now lets focus on the first equation \"3-6x=-15\"\r
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\n" ); document.write( "\n" ); document.write( "\"-6x=-15-3\"Subtract 3 from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"-6x=-18\" Combine like terms on the right side\r
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\n" ); document.write( "\n" ); document.write( "\"x=%28-18%29%2F%28-6%29\" Divide both sides by -6 to isolate x\r
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\n" ); document.write( "\n" ); document.write( "\"x=3\" Divide\r
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\n" ); document.write( "\n" ); document.write( "Now lets focus on the second equation \"3-6x=15\"\r
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\n" ); document.write( "\n" ); document.write( "\"-6x=15-3\"Subtract 3 from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"-6x=12\" Combine like terms on the right side\r
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\n" ); document.write( "\n" ); document.write( "\"x=%2812%29%2F%28-6%29\" Divide both sides by -6 to isolate x\r
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\n" ); document.write( "\n" ); document.write( "\"x=-2\" Divide\r
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\n" ); document.write( "\n" ); document.write( "So the solutions to \"abs%283-6x%29=15\" are:\r
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\n" ); document.write( "\n" ); document.write( "\"x=3\" and \"x=-2\"\r
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\n" ); document.write( "\n" ); document.write( "Notice if we graph \"y=abs%283-6x%29\" and \"y=15\" (just set each side equal to y and graph), we get\r
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\n" ); document.write( "\n" ); document.write( "\"graph%28500%2C500%2C-4%2C5%2C-5%2C18%2Cabs%283-6x%29%2C15%29\" Graph of \"y=abs%283-6x%29\" (red) and \"y=15\"(green)\r
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\n" ); document.write( "\n" ); document.write( "and we can see the two graphs intersect at \"x=3\" and \"x=-2\". So this verifies our answer.\r
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