document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=142020>Question 142020</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the value of the 50th term of the series: 180+162+145.8+131.22+... </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #103429 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=103429\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the value of the 50th term of the series: 180+162+145.8+131.22+...<BR>\n" );
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document.write( "162/180 = 0.9<BR>\n" );
document.write( "145.8/162 = 0.9<BR>\n" );
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document.write( "So the series is geometric with r = 0.9<BR>\n" );
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document.write( "a(50) = a(1)*r^49<BR>\n" );
document.write( "a(50) = 180*0.9^49 = 1.030755041....<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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