document.write( "Question 21456: THE LENGTH OF A RECTANGULAR FIELD IS 20 FT LESS THAN TWICE ITS WIDTH. ITS AREA IS 6000 SQ FT. FIND THE LENGTH AND WIDTH.\r
\n" ); document.write( "\n" ); document.write( "I KNOW AREA=L TIMES W
\n" ); document.write( "BUT I CANT QUITE FIGURE OUT HOW TO SET IT UP.
\n" ); document.write( "LENGTH 2W-20=6000 ??????????
\n" ); document.write( "THANKS!
\n" ); document.write( "

Algebra.Com's Answer #10341 by Paul(988)\"\" \"About 
You can put this solution on YOUR website!
(x)(2x-20)=6000
\n" ); document.write( "\"2x%5E2-20x=6000\"
\n" ); document.write( "\"2x%5E2-20x-6000=0\"
\n" ); document.write( "Use quadratic formula:
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "a=2, b=-20, c=-6000
\n" ); document.write( "\"x+=+%28-%28-20%29+%2B-+sqrt%28+%28-20%29%5E2-4%282%29%28-6000%29+%29%29%2F%282%282%29%29+\"
\n" ); document.write( "\"x+=+%2820%29+%2B-+sqrt%28+400%2B48000+%29%29%2F%284%29\" (divide by four)
\n" ); document.write( "\"x+=+%2820%29+%2B-+sqrt%28+48400+%29%29%2F4+\" (divide by four)
\n" ); document.write( "Add (don't subtract): \"x=240%2F4\"
\n" ); document.write( "x=60
\n" ); document.write( "2(60)-20=100
\n" ); document.write( "hence the width is 60ft and the length is 100ft.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );