document.write( "Question 141988: Describe the procedure used to write the standard equation of the ellipse defined by \"+9x%5E2%2B4y%5E2%2B18x-40y%2B73=0+\" \n" ); document.write( "
Algebra.Com's Answer #103398 by jim_thompson5910(35256)\"\" \"About 
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\"9x%5E2%2B4y%5E2%2B18x-40y%2B73=0\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"9x%5E2%2B18x%2B4y%5E2-40y%2B73=0\" Rearrange the terms\r
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\n" ); document.write( "\n" ); document.write( "\"9x%5E2%2B18x%2B4y%5E2-40y=-73\" Subtract \"73\" from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"9%28x%2B1%29%5E2-9%2B4y%5E2-40y=-73\" Complete the square for the x terms\r
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\n" ); document.write( "\n" ); document.write( "\"9%28x%2B1%29%5E2-9%2B4%28y-5%29%5E2-100=-73\" Complete the square for the y terms\r
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\n" ); document.write( "\n" ); document.write( "\"9%28x%2B1%29%5E2%2B4%28y-5%29%5E2-109=-73\" Combine like terms\r
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\n" ); document.write( "\n" ); document.write( "\"9%28x%2B1%29%5E2%2B4%28y-5%29%5E2=-73%2B109\" Add \"109\" to both sides\r
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\n" ); document.write( "\n" ); document.write( "\"9%28x%2B1%29%5E2%2B4%28y-5%29%5E2=36\" Combine like terms\r
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\n" ); document.write( "\n" ); document.write( "\"%289%28x%2B1%29%5E2%2B4%28y-5%29%5E2%29%2F%2836%29=%2836%29%2F%2836%29\"Now divide both sides by 36 to make the right side equal to 1\r
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\n" ); document.write( "\n" ); document.write( "\"%289%28x%2B1%29%5E2%29%2F%2836%29%2B%284%28y-5%29%5E2%29%2F%2836%29=1\" Break up the fraction\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B1%29%5E2%2F%284%29%2B%28y-5%29%5E2%2F%289%29=1\" Reduce\r
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\n" ); document.write( "\n" ); document.write( "So the equation is now in the standard form of an ellipse \"%28x-h%29%5E2%2F%28a%5E2%29%2B%28y-k%29%5E2%2F%28b%5E2%29=1\" where \"h=-1\", \"k=5\", \"a=2\", and \"b=3\"\r
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