document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=141967>Question 141967</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A sample of 25 concession stand purchases at the October 22 matinee of Bride of Chucky showed<BR>\n" );
document.write( "a mean purchase of $5.29 with a standard deviation of $3.02. For the October 26 evening showing<BR>\n" );
document.write( "of the same movie, for a sample of 25 purchases the mean was $5.12 with a standard deviation of<BR>\n" );
document.write( "$2.14. The means appear to be very close, but not the variances. At &#945; = .05, is there a difference<BR>\n" );
document.write( "in variances? Show all steps clearly, including an illustration of the decision rule. (Data are from<BR>\n" );
document.write( "a project by statistics students Kim Dyer, Amy Pease, and Lyndsey Smith.)<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #103384 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=103384\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Previously answered.<BR>\n" );
document.write( "Go to www.algebra.com<BR>\n" );
document.write( "Use the search bar to find 135744<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );