document.write( "Question 141919: Each of the three dimensions of a cube with a volume of y^3 cubic centimeters is decreased by
\n" ); document.write( "a whole number of centimeters. If the new volume is y^3-13y^2+54y-72 cubic centimeters and the new width is y-6 centimeters, then what are the new length and height? \n" ); document.write( "
Algebra.Com's Answer #103382 by ankor@dixie-net.com(22740)\"\" \"About 
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Each of the three dimensions of a cube with a volume of y^3 cubic centimeters is
\n" ); document.write( " decreased by a whole number of centimeters. If the new volume is y^3-13y^2+54y-72
\n" ); document.write( " cubic centimeters and the new width is y-6 centimeters, then what are the new length and height?
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\n" ); document.write( "Use synthetic division to divide the new volume by the width
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\n" ); document.write( "....__________________
\n" ); document.write( "+6|1 - 13 + 54 - 72
\n" ); document.write( "..........+ 6 - 42 + 72
\n" ); document.write( ".......----------------
\n" ); document.write( "......1 - 7 + 12 + 0
\n" ); document.write( "That gives us:
\n" ); document.write( "y^2 - 7y + 12 = 0
\n" ); document.write( "Factors to
\n" ); document.write( "(y-4)(y-3) = 0
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\n" ); document.write( "y = 4, y = 3; the length and height
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