document.write( "Question 21453: I just submitted this and forgot to give my email address:
\n" ); document.write( "I am working Factoring polynominals completely. I can't figure out a solution for this one.
\n" ); document.write( "2x (exponent of 3) -10x (exponent of 2) + 12x \r
\n" ); document.write( "\n" ); document.write( "Please help - thanks so much!!
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Algebra.Com's Answer #10337 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Factor:
\n" ); document.write( "\"2x%5E3+-+10x%5E2+%2B+12x\" First, factor 2x from this expression.
\n" ); document.write( "\"2x%28x%5E2+-+5x+%2B+6%29\" Now factor the parentheses. The factors will look like (x - a)(x - b)
\n" ); document.write( "What are a and b? You need (a)(b) = 6 for the constant term and (a)+(b) = -5 for the x-coefficient.
\n" ); document.write( "Try: a = -2 and b = -3
\n" ); document.write( "(-2)(-3) = 6
\n" ); document.write( "(-2)+(-3) = -5
\n" ); document.write( "These will work, so the factors are (x - 2)(x - 3).
\n" ); document.write( "Putting it all together, we have:
\n" ); document.write( "\"2x%5E3+-+10x%5E2+%2B+12x+=+2x%28x+-+2%29%28x+-+3%29\"
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