document.write( "Question 141880: how do I factor this polynomial? Thank you for your help :)
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\n" ); document.write( "64x to the second -81. \n" ); document.write( "

Algebra.Com's Answer #103365 by Fombitz(32388) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"64x%5E2-81\"$
\n" ); document.write( "This polynomial is of the form
\n" ); document.write( " $\"z%5E2-a%5E2\"$
\n" ); document.write( "which factors to
\n" ); document.write( " $\"z%5E2-a%5E2=%28z-a%29%28z%2Ba%29\"$
\n" ); document.write( "Let's look at each of the expressions.
\n" ); document.write( " $\"z%5E2=64x%5E2\"$
\n" ); document.write( " $\"z=8x\"$
\n" ); document.write( " $\"a%5E2=81\"$
\n" ); document.write( " $\"a=9\"$
\n" ); document.write( "So when you plug that in, you get,
\n" ); document.write( " $\"64x%5E2-81=%288x-9%29%288x%2B9%29\"$ \n" ); document.write( "

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