document.write( "Question 141814This question is from textbook
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document.write( ": how do you find the area of a regular pentagon with radius 10cm? \n" );
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Algebra.Com's Answer #103361 by edjones(8007)![]() ![]() You can put this solution on YOUR website! r=10, s=side length, n=number of sides, A=area \n" ); document.write( "For any regular polygon: r=s/(2sin(pi/n)) using radians. \n" ); document.write( "10=s/(2sin(pi/5)) \n" ); document.write( "10=s/1.17557... \n" ); document.write( "s=11.76... \n" ); document.write( ". \n" ); document.write( "Heron's Law: \n" ); document.write( "Let a=10, b=10, c=11.76 \n" ); document.write( "s=(a+b+c)/2 Don't confuse this s with the s above which is now c. This is a new s. \n" ); document.write( "=(10+10+11.76)/2 \n" ); document.write( "=15.88... \n" ); document.write( "A=sqrt(s(s-a)(s-b)(s-c)) Area of the triangle \n" ); document.write( "=sqrt(15.88(15.88-10)(15.88-10)(15.88-11.76)) \n" ); document.write( "=47.56 \n" ); document.write( "47.56*5=237.8 cm^2 Area of the pentagon. \n" ); document.write( ". \n" ); document.write( "Ed \n" ); document.write( " |