document.write( "Question 141814This question is from textbook
\n" ); document.write( ": how do you find the area of a regular pentagon with radius 10cm? \n" ); document.write( "
Algebra.Com's Answer #103361 by edjones(8007)\"\" \"About 
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r=10, s=side length, n=number of sides, A=area
\n" ); document.write( "For any regular polygon: r=s/(2sin(pi/n)) using radians.
\n" ); document.write( "10=s/(2sin(pi/5))
\n" ); document.write( "10=s/1.17557...
\n" ); document.write( "s=11.76...
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\n" ); document.write( "Heron's Law:
\n" ); document.write( "Let a=10, b=10, c=11.76
\n" ); document.write( "s=(a+b+c)/2 Don't confuse this s with the s above which is now c. This is a new s.
\n" ); document.write( "=(10+10+11.76)/2
\n" ); document.write( "=15.88...
\n" ); document.write( "A=sqrt(s(s-a)(s-b)(s-c)) Area of the triangle
\n" ); document.write( "=sqrt(15.88(15.88-10)(15.88-10)(15.88-11.76))
\n" ); document.write( "=47.56
\n" ); document.write( "47.56*5=237.8 cm^2 Area of the pentagon.
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\n" ); document.write( "Ed
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