document.write( "Question 141858: A consumer electronics company sells 6.7 million MP3 players per month at a price of $100 apiece; when the price is lowered to $80, the company sells 10.2 million players per month. How many MP3 players can the company expect to sell per month at a price of $75? \n" ); document.write( "
Algebra.Com's Answer #103325 by stanbon(75887)\"\" \"About 
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A consumer electronics company sells 6.7 million MP3 players per month at a price of $100 apiece; when the price is lowered to $80, the company sells 10.2 million players per month. How many MP3 players can the company expect to sell per month at a price of $75?
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\n" ); document.write( "You have two points: (100,6.7) (80,10.2)
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\n" ); document.write( "slope = (6.7-10.2)/(100-80) = -3.5/20 = -0.175 million/dollars
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\n" ); document.write( "Form: selling # = (slope)(cost) + b
\n" ); document.write( "10.2 = -0.175(80) + b
\n" ); document.write( "b = 24.2
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\n" ); document.write( "EQUATION:
\n" ); document.write( "selling # = -0.175(cost) + 24.2
\n" ); document.write( "How many MP3 players can the company expect to sell per month at a price of $75?
\n" ); document.write( "selling#(75) = -0.175*75 + 24.2
\n" ); document.write( "selling#(75) = 11.075 million
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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