document.write( "Question 141833: Find a counterexample to show that the following statement is incorrect:
\n" ); document.write( "\"The sum of any two odd numbers is divisible by 4\"
\n" ); document.write( "If I try 1 + 5 = 6, 6/4 = 3/2, does this disprove the above statement? \n" ); document.write( "
Algebra.Com's Answer #103317 by jojo14344(1513)\"\" \"About 
You can put this solution on YOUR website!
If you start with #1 then add the next higher odd #, the chance of being divisible by 4 is 50%. Meaning the 1st sequence of odd #'s will be, then the next won't, next will be, next won't, next will be...next won't. To show,
\n" ); document.write( "Starting at 1,
\n" ); document.write( "1+3=4, yes
\n" ); document.write( "1+5=6, no
\n" ); document.write( "1+7=8, yes
\n" ); document.write( "1+9=10, no
\n" ); document.write( "1+11=12, yes
\n" ); document.write( "1+13=14, no
\n" ); document.write( "1+15=16, yes
\n" ); document.write( "1+17=18, no
\n" ); document.write( "1+19=20, yes...
\n" ); document.write( "So you see the sequence, it is every other pair it is divisible by 4.
\n" ); document.write( "Hope this help.
\n" ); document.write( "Thank You,
\n" ); document.write( "Jojo \n" ); document.write( "
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