document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=21447>Question 21447</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If 2 numbers have a product of 75, a quotient of 3, and a difference of 10, what's the sum of these 2 numbers? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #10331 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=10331\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the 2 numbers be x and y .we have <BR>\n" );
document.write( "xy=75.......I..........<BR>\n" );
document.write( "x/y=3.................II.<BR>\n" );
document.write( "x-y=10....................III<BR>\n" );
document.write( ".actually 2 relations should do to solve the problem<BR>\n" );
document.write( "from II,we have....x/y=3<BR>\n" );
document.write( "x=3y.......<BR>\n" );
document.write( "substituting in I we get <BR>\n" );
document.write( "xy=3y*y=75<BR>\n" );
document.write( "y*y=75/3=25<BR>\n" );
document.write( "y=5<BR>\n" );
document.write( "so x =3y=3*5=15<BR>\n" );
document.write( "so 5 and 15 are the 2 numbers .incidentally this satoisfies the third relation of x-y =15-5=10...so no problem this is the answer...otherwise we would have to say NO ANSWER!!!! </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );