document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=141756>Question 141756</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The diagonal of a rectangle is 20 in long. The rectangle's length is 3 times its width. Find the length of the rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #103273 by </B><A HREF=/tutors/aboutme.mpl?userid=Shifa><B>Shifa(4)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Shifa><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=103273\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Diagonal of rectangle=20<BR>\n" );
document.write( "Breadth of rectangle=x<BR>\n" );
document.write( "Length of rectangle=3x<BR>\n" );
document.write( "Therefore by pythagoros theorem,<BR>\n" );
document.write( " \"3x\"square + \"x\"square=\"20\"square<BR>\n" );
document.write( " \"4x\"square = 400<BR>\n" );
document.write( "  \"x\"square = 400/4<BR>\n" );
document.write( "  \"x\"square = 100<BR>\n" );
document.write( "   x = 10<BR>\n" );
document.write( " <BR>\n" );
document.write( "Thus, Breadth = 10<BR>\n" );
document.write( "      Length = 3x<BR>\n" );
document.write( "             = 3*10<BR>\n" );
document.write( "             = 30 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );