document.write( "Question 141732: Q1.THE greatest term of series
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document.write( "2^1/2,3^1/3,4^1/4,.........,100^1/100 will be\r
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document.write( "Q2.Sum of the solution of the equation
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document.write( "2.8^x+32.8^-x=65 \n" );
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Algebra.Com's Answer #103260 by stanbon(75887) ![]() You can put this solution on YOUR website! Q1.THE greatest term of series \n" ); document.write( "2^1/2,3^1/3,4^1/4,.........,100^1/100 will be \n" ); document.write( "Ans: 2^(1/2) \n" ); document.write( "-----------------------\r \n" ); document.write( "\n" ); document.write( "Q2.Sum of the solution of the equation \n" ); document.write( "2.8^x+32.8^-x=65 \n" ); document.write( "Solution #1 = -1.194661... \n" ); document.write( "Solution #2 = 4.0543012... \n" ); document.write( "------ \n" ); document.write( "Add those to get the sum. \n" ); document.write( "============= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |